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why Mathematica 10 does not compute this integral?

Posted 9 years ago
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enter image description here

Why does Mathematica 10 not compute the first one, but compute the second one? Please try the attached file. Thank you.

Attachments:
POSTED BY: Hong Liu
8 Replies

Thanks. Palm slap to forehead.... I saw that it had moved the following day. I would have never survived in the wild.

I am wondering if that icon needs some words above or beside it, such as "Use this for Posting Code"? I don't find <> is obvious for its purpose.

POSTED BY: W. Craig Carter

I didn't find it obvious either. While I prefer the new location, it took me a bit to figure out what had changed (and thus why my code sections did not format correctly).

POSTED BY: Daniel Lichtblau

Hello Because v appears as the integration variable as a subscript. Try

Integrate[E^(1/2 (-(v^2/ \!(*SubsuperscriptBox[([Sigma]), (vvvv), (2)]))))/ Sqrt[2 [Pi]] , {v, -Infinity, Infinity}]

For some reason the "code block <>" is not appearing on this community editor. Sorry, cut and paste should work. Adding an image even though this is "bad practice" enter image description here

POSTED BY: W. Craig Carter

The code block ikon moved left in the edit row.

enter image description here

POSTED BY: Bruce Miller

The integration you are trying to compute will not give you any answer because the constant 'sigma v' has a subscript v which is considered as a variable v which runs from (-) Infinity to (+) Infinity. As Mathematica does not know that it is a subscript or a notation,it can not compute. That is why it is convenient to use another symbol say, 'a' instead of 'sigma v'.

Integrate[Exp[(-v^2/a^2)/2]/(Sqrt[2 Pi] a), {v, -Infinity, Infinity}]

Perhaps this will work. See the attachment.

Attachments:
POSTED BY: suvadip mandal

Sorry Suvadip, You had answered while I was creating a response.

POSTED BY: W. Craig Carter

Hi Craig,

Please do not mind.

sincerely, Suvadip.

POSTED BY: suvadip mandal
Posted 9 years ago

Thank you very much! That explains.

POSTED BY: Hong Liu
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