Message Boards

WOLFRAM COMMUNITY

8015 Views

5 Replies

3 Total Likes

View groups...

Follow this post

Share this post:

GROUPS:

Mathematics Mathematica Calculus

FindRoot and two Parametric Functions

Derek Smith

Posted 10 years ago

I am trying to find the three intersection points of r1[t] = {2 Cos[t], 2 Sin[t]} and r2[t] = {3 Cos[t], Sin[t] - 1} using FindRoot but keep getting various error messages no matter what I do. Any help is appreciated. Also, I would like to designate them both as the same variable but give them different colors using PlotStyle. Currently I am only able to do so by designating them as two separate variables. I am new to mathematica so please be as basic as possible. Code is attached. Attachments:

POSTED BY: Derek Smith

5 Replies

Sort By:

Frank Kampas

Frank Kampas, Physicist at Large Consulting

Posted 10 years ago

The value of t in r1 is not the same as the value of t in r2 when the curves intersect. Here's one way to find the intersections: In[1]:= r1[t_] = {2 Cos[t], 2 Sin[t]}; In[2]:= r2[t_] = {3 Cos[t], Sin[t] - 1}; In[17]:= r = Reduce[{r1[t1] == r2[t2], 0 <= t1 <= 2 \[Pi], 0 <= t2 <= 2 \[Pi]}, {t1, t2}] Out[17]= (t1 == (3 \[Pi])/2 && t2 == (3 \[Pi])/2) \|\| (t1 == 2 \[Pi] - 2 ArcTan[8 - 3 Sqrt[7]] && t2 == 2 ArcTan[(-53 + 20 Sqrt[7])/(3 (-8 + 3 Sqrt[7]))]) \|\| (t1 == 2 \[Pi] - 2 ArcTan[8 + 3 Sqrt[7]] && t2 == 2 ArcTan[(53 + 20 Sqrt[7])/(3 (8 + 3 Sqrt[7]))]) In[23]:= r1[t1] /. {ToRules[r]} Out[23]= {{0, -2}, {2 Cos[2 ArcTan[8 - 3 Sqrt[7]]], -2 Sin[ 2 ArcTan[8 - 3 Sqrt[7]]]}, {2 Cos[ 2 ArcTan[8 + 3 Sqrt[7]]], -2 Sin[2 ArcTan[8 + 3 Sqrt[7]]]}} In[24]:= N[%] Out[24]= {{0., -2.}, {1.98431, -0.25}, {-1.98431, -0.25}}

The value of t in r1 is not the same as the value of t in r2 when the curves intersect. Here's one way to find the intersections:

In[1]:= r1[t_] = {2 Cos[t], 2 Sin[t]};

In[2]:= r2[t_] = {3 Cos[t], Sin[t] - 1};

In[17]:= r = 
 Reduce[{r1[t1] == r2[t2], 0 <= t1 <= 2 \[Pi], 
   0 <= t2 <= 2 \[Pi]}, {t1, t2}]

Out[17]= (t1 == (3 \[Pi])/2 && 
   t2 == (3 \[Pi])/2) || (t1 == 2 \[Pi] - 2 ArcTan[8 - 3 Sqrt[7]] && 
   t2 == 2 ArcTan[(-53 + 20 Sqrt[7])/(3 (-8 + 3 Sqrt[7]))]) || (t1 == 
    2 \[Pi] - 2 ArcTan[8 + 3 Sqrt[7]] && 
   t2 == 2 ArcTan[(53 + 20 Sqrt[7])/(3 (8 + 3 Sqrt[7]))])

In[23]:= r1[t1] /. {ToRules[r]}

Out[23]= {{0, -2}, {2 Cos[2 ArcTan[8 - 3 Sqrt[7]]], -2 Sin[
    2 ArcTan[8 - 3 Sqrt[7]]]}, {2 Cos[
    2 ArcTan[8 + 3 Sqrt[7]]], -2 Sin[2 ArcTan[8 + 3 Sqrt[7]]]}}

In[24]:= N[%]

Out[24]= {{0., -2.}, {1.98431, -0.25}, {-1.98431, -0.25}}

POSTED BY: Frank Kampas