I need to find the derivative of this function y = ?(2+5x) and evaluate it at x = 1 Hoping there is a simple way to accomplish this.
see http://reference.wolfram.com/language/ref/D.html
Mathematica:
y = ?(2+5x); Y = D[y,x]; x =1; Y
Wolframalpha:
D(sqrt(2+5x),x)
click
D(sqrt(2+5x),x) at x=1
worked for me.
http://www.current.wolframalpha.com/input/?i=D%28sqrt%282%2B5x%29%2Cx%29+++at+x%3D1
