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# How to get the roots of an equation

Posted 10 years ago
 Hallo. I am dealing with a very simple problem of non-linear magnetic circuit. Thus, by solving the equation that gives me point of operatio, that is the real root, I cannot have it to manipulate for the sequence calculus. Would someone help me, please ? The Palette is attached. Attachments:
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Posted 10 years ago
 Reduce[0.1333*H*H/(95*95 + H*H) - k*(Nesp*Ix - H*lm) == 0, H, Reals] returns H == 167.894 but that will not always work without warnings or errors from some problems
Posted 10 years ago
 You can also remove the warning messages by using equivalent fractions instead of the decimals, for instance use 2/15 instead of 0.1333333. Use Rationalize[0.1333333333] to do that for you. All instances of decimal must be removed before the message disappears.Paul
Posted 10 years ago
 Hi Sergio I think I know where you want to go with this. I'm sure there are more elegant ways to achieve this but this is what I do to extract results for further use. If we set the calculation like this p = Solve[0.1333*H*H/(95*95 + H*H) - k*(Nesp*Ix - H*lm) == 0, H, Reals]; p = FromDigits[H /. p] the variable p is now your new result, thus 167.894 we can now use this in the follow up (0.133*p^2)/(95^2 + p^2) giving this 0.100745Hope this helps a littlePaul.
Posted 10 years ago
 Thank you, Bill and Paul. But I think my question was not so clear. I mean, what if I want to take that value for H to continue with a sequence of calculation ?For example , B=H*H ? Scabral
Posted 10 years ago
 Thank you so much, Paul ! It does work !! Scabral