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GROUPS:

Derive in a point a

Posted 11 years ago
POSTED BY: peter B
2 Replies
Posted 11 years ago

And this:

g[x_] := ArcTan[x]^2 + ArcSin[x/2];

dg[x_] = D[g[x], x];

p1 = Plot[{g[x], dg[x]}, {x, -2, 2}, PlotLegends -> "Expressions", 
  Epilog -> {PointSize[0.02], Point[{1, g[1]}]}]

enter image description here

In[4]:= (* dg[x_]= was used rather than dg[x_]:= because we want the \
right hand side evaluated before the rule is defined. Look up Set and \
SetDelayed. *)

In[5]:= (* = would work here as well, but := is used more often *)
f[x_] := 3 x + 1; (* defines a function *)

In[6]:= f[a] (* evaluates it at a *)

Out[6]= 1 + 3 a

In[7]:= f[1]

Out[7]= 4
POSTED BY: David Keith
Posted 11 years ago

This?

In[1]:= D[ArcTan[x]^2 + ArcSin[x/2], x]

Out[1]= 1/(2 Sqrt[1 - x^2/4]) + (2 ArcTan[x])/(1 + x^2)

In[2]:= % /. x -> 1

Out[2]= 1/Sqrt[3] + \[Pi]/4
POSTED BY: Bill Simpson
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