Why limit sqrt(x) = 0 , if x->0. Real function sqrt (x) is one-sided at the point x = 0.
If x is generalized to a complex number z, then lim ?z as z->0 is still 0. For z represented in polar form r exp[i phi], lim as r->0 is again 0.
Thx, But it seems to me a week ago, at the same request wolfram posted one-sided real limit 0 and a second complex.
