Group Abstract Group Abstract

Message Boards Message Boards

1
|
12.8K Views
|
9 Replies
|
4 Total Likes
View groups...
Share
Share this post:

How to get perfect square from the list element..

Posted 11 years ago

Hi All, I need some help to solve this problem.. Assume you have n=1,2,3,...,15 number. Put them in an order so that when you add two successive number you get perfect square. As seen one example below. 9+7=16, 7+2=9, 2+14=16, and so on. I did this using pen and paper work.. I tried to solve this using Mathematica. First I got a set of number that make each number perfect square.. But I don't know what should be next step. I tried to use graph but it takes time and is easy to make error (has not been completed yet). I also want to extend it to say n=25.. Any help appreciated. Thanks..

when n=15---->9-7-2-14-11-5-4-12-13-3-6-10-15-1-8

when n=16----> 16-9-7-2-14-11-5-4-12-13-3-6-10-15-1-8

when n=17----> 16-9-7-2-14-11-5-4-12-13-3-6-10-15-1-8-17

when n=18----> no sequences

when n=19----> no sequences

when n=20----> I claimed no sequences

It Must start with 18 since there is only one number make it perfect square namely 7. 18+7 but after this we have two options. 18+7+2 or 18+7+9

Please see attachment..

Reply to this discussion
Community posts can be styled and formatted using the Markdown syntax.
Reply Preview
Attachments
Remove
or Discard
Be respectful. Review our Community Guidelines to understand your role and responsibilities. Community Terms of Use