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Mathematica

Can you extract variables from a list of equations?

Conor Nelson
Posted 10 years ago

Given a list of equations (or inequalities) I wish to find all the variables in said list. Example:

{x >= 0, y >= 0, z >= 0, 2 x >= y, 2 z >= y, 2 x + y <= 4, 2 z + y <= 4};
-or-
{x1 >= 0, x2 >= 0, x3 >= 0, 2 x1 >= x2, 2 x3 >= x2, 2 x1 + x2 <= 4, 2 x3 + x2 <= 4}

This will generate:

{x,y,z}
-or
{x1,x2,x3}

Respectively. Ive tried to use Variables, however, Variables is only for expressions. Is this even possible?
POSTED BY: Conor Nelson
2 Replies
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This will return all symbols at level -1 that are not heads and not numeric:

vars[expr_] := Union@Cases[expr, s_Symbol /; Not@NumericQ[s], {-1}]

vars[{x >= 0, y >= 0, z >= 0, 2 x >= y, 2 z >= y, 2 x + y <= 4, 2 z + y <= 4}]
(* {x,y,z} *)

Why not heads and not numeric? So vars[Sin[x] + Pi] will give only x but not Sin or Pi.

Be cautious when using this solution. I'm sure it wouldn't be hard to find cases when it returns symbols it shouldn't. It also doesn't handle non-symbol variables such as x[1] in x[1]^2+1, or subscripted ones such as $x_1$. Variables does handle these. But variables only handles polynomials, e.g. Variables[Sin[x]] --> {Sin[x]}.
POSTED BY: Szabolcs Horvát

Try this:

list = {x1 >= 0, x2 >= 0, x3 >= 0, 2 x1 >= x2, 2 x3 >= x2, 2 x1 + x2 <= 4, 2 x3 + x2 <= 4} ;
Variables[Part[list,All,1]]
Variables[Apply[List,list,1]]

I.M.
POSTED BY: Ivan Morozov
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