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Vigenère cipher/Cryptanalysis

Luis Ledesma
Posted 10 years ago
POSTED BY: Luis Ledesma
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POSTED BY: Sander Huisman

Sander, does all this necromancy make us, umm, "visionaires"?
POSTED BY: Daniel Lichtblau

And other functions who might be useful are: 

ResourceFunction["VigenereDecipher"]
ResourceFunction["VigenereCipher"]

(and yes, years after the fact as well)
POSTED BY: Sander Huisman

I added an example showing one way to attack this cipher in ResourceFunction["IrregularPeriodogram"].

[I realize this is years after the fact.]
POSTED BY: Daniel Lichtblau

Your position differences for the four times repeated trigram "XJE" are all divisible by 14. All but one difference for the thrice-repeated trigrams is divisible by 14. I think I would assume that one was an accidental repeat (due to actually different plain text trigrams getting the same encoding). So expect a key length of 7 or 14 because 2 is too short. Also there is no reason to ignore the doubly-repeated cases, and they might give similar information (I have not checked).
POSTED BY: Daniel Lichtblau
Luis Ledesma
Luis Ledesma
Posted 10 years ago

Does any literature that i recommend? Or something that can help me solve this problem, because it took several attempts and i have not been able to resolve, i've noticed the closer look at the page that i shared that the key is

:THECHESHIRECAT

but I still don't know how get it using Mathematica,greetings to all..

POSTED BY: Luis Ledesma
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