Daniel,

Thanks for replying to my post. I tried to be brief, and maybe it appeared to be too brief. Let me try to explain it again.

First, the "ComplicatedFunction" is to is designed for a numeric input. A real number. Giving it a symbolic input will choke it. The Documentation states:

"FindRoot first localizes the values of all variables, then evaluates f with the variables being symbolic, and then repeatedly evaluates the result numerically."

This is consistent with my observation that a symbolic variable is passed instead of a numeric value. The result of the print statement is:

        this is x: x

instead of:

        this is x: 0.83

I googled the problem extensively last night and discovered that mathematica offers a means of limiting the input of a function, and by doing so get it to fail on the symbolic pass. f(x_} becomes:

f(x_?NumberQ}

This appears to work on for a small test case. The actual case now gives me an error:

FindRoot::nveq: "The number of equations does not match the number of variables in FindRoot[{radRRunFun[r]==0},{r,radRF$319342}].

Let me work on this again and see if I can find a solution on my own.