# [GIF] Scherk surface and family resemblance

Posted 3 years ago
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| Family ResemblanceThis is an isometric projection of one fundamental domain of the Scherk surface and its associate family. This is obviously not a projection that reveals much of the geometry of the surface, but I like how it visually recalls string art parabolas. Here's the code for the corresponding Manipulate object: scherk[u_, v_, \[Theta]_] := Re[E^(I \[Theta]) {ArcTanh[z], I ArcTan[z], I ArcTanh[z^2]} /. z -> u + I v] Manipulate[Module[{a, projector}, a = .99; projector = {{1, 0, 0}, {0, 1, 0}}; Show[ParametricPlot[ Table[projector.scherk[u, v, \[Theta]], {u, -a, a, a/10}], {v, -a, a}, PlotRange -> 3.5, Axes -> False, PlotStyle -> Directive[Thickness[.0045], RGBColor["#fbfbfb"]]], ParametricPlot[ Table[projector.scherk[u, v, \[Theta]], {v, -a, a, a/10}], {u, -a, a}, PlotStyle -> Directive[Thickness[.0045], RGBColor["#fbfbfb"]]], ImageSize -> 540, Background -> RGBColor["#08327d"]]], {\[Theta], 0, \[Pi]}] I originally wrote this as a single ParametricPlot using projector.# & /@ {scherk[u, v, \[Theta]], scherk[v, u, \[Theta]]}, but breaking the mesh drawing code into two separate ParametricPlots ended up being considerably faster. (Also, note that I've projected down to 2D, which generally seems to lead to higher image quality and faster processing.)Here's a more conventional projection of the same surface: And here's the code for this view: Manipulate[Module[{a, projector}, a = .99; projector = {{1, 0, 0}, {0, 1, 0}}; Show[ParametricPlot3D[ Table[scherk[u, v, \[Theta]], {u, -a, a, a/10}], {v, -a, a}, PlotRange -> 3.5, Axes -> None, Boxed -> False, ViewAngle -> \[Pi]/12, PlotStyle -> Directive[Thickness[.0045], RGBColor["#fbfbfb"]]], ParametricPlot3D[ Table[scherk[u, v, \[Theta]], {v, -a, a, a/10}], {u, -a, a}, PlotStyle -> Directive[Thickness[.0045], RGBColor["#fbfbfb"]]], ImageSize -> 540, Background -> RGBColor["#08327d"]]], {\[Theta], 0, 2 \[Pi]}] Answer
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Posted 3 years ago
 This is very beautiful, thank you for sharing ! Answer
Posted 3 years ago
 Thanks! Answer
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