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Get right results with binomial functions in MMA 7?

Posted 9 years ago

Hello all,

I am using Mathematica version 7 and would like to ask a question to those using newer versions.

The expression

t1 = Sum[ j Binomial[A, j] Binomial[B, n - j], {j, 0, n}]

can be calculated by pencil and paper giving as result

A Binomial[ A + B - 1, n - 1]

while evaluating the expression for t1 (on my system) yields

-(((-1)^n A (-1 - A - B + n)!)/((-A - B)! (-1 + n)!))

Feeding numbers to it gives

In[58]:= A Binomial[ A + B - 1, n - 1] /. A -> 7 /. B -> 5 /. n -> 4

Out[58]= 1155

but

In[60]:= t1 /. A -> 7 /. B -> 5 /. n -> 4

Out[60]= 0

Obviously something is severely wrong!

The same thing comes along with

In[15]:= t2 = Sum[ j^2  Binomial[A, j] Binomial[B, n - j], {j, 0, n}]

    Out[15]= ((-1)^n A (B - n + A n) (-1 - A - B + n)!)/((1 - A - B)! (-1 + n)!)

which is evaluated by the paper and pencil method to

A (A - 1 + (A + B - 1)/(n - 1)) Binomial[A + B - 2, n - 2]

with striking differences when you feed numbers in.

What do the newer versions of Mma say to this?

Regards, Hans Dolhaine

POSTED BY: Hans Dolhaine
5 Replies

You can use this link:

Support

How to do this?

POSTED BY: Hans Dolhaine

If this is an unknown bug, you must/can submit it to the support.

Hello, thanks. That is sort of much better, but the result for t2 is still, say, less than optimal. (Try to give numbers into t2 and compare this with the correct pencil&paper result)

POSTED BY: Hans Dolhaine

MMa 11 says:

In[1]:= t1 = Sum[j Binomial[A, j] Binomial[B, n - j], {j, 0, n}]

Out[1]= A Binomial[-1 + A + B, -1 + n]

In[2]:= % /. {A -> 7, B -> 5, n -> 4}

Out[2]= 1155

In[3]:= t2 = Sum[j^2 Binomial[A, j] Binomial[B, n - j], {j, 0, n}]

Out[3]= ((-1)^n A (B - n + 
   A n) (-1 - A - B + n)!)/((1 - A - B)! (-1 + n)!)
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