if the output:
Range [1,10]
is: {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
how can I get:
{001, 002, 003, 004, 005, 006, 007, 008, 009, 010} ?
with 3, or other, exact number of digits?
tnk's
That is also very nice solution! You can't really do anything with AccountingForm except for display, if you want to export something or concatenate with other words/characters you'll need strings....
If output with Strings is okay, then you can also write-
IntegerString[#, 10, 3] & /@ Range[1, 100]
Dear @Mutatis Mutandis you do not need to format code as bold font type. There is a proper formatting for code as you can see in many posts on this forum. Please learn about proper posting here: https://wolfr.am/READ-1ST
AccountingForm does not return strings, which is what the OP probably wants:
StringPadLeft[ToString[#], 3, "0"] & /@ Range[1, 10]
StringPadLeft (for string) or PadLeft (for lists) can be used to pad to a fixed number of characters/items.
If you mean selectively padding the 1 or 2 digit numbers with leading zeroes, then you can rewrite [what Nasser has suggested]-
Range[1, 105] /.x_ /; IntegerLength[x] < 3 ->AccountingForm[x, 2, NumberPadding -> {"0", ""}]
It works for numbers 1 or 2 digits, but the reason why I want to get the output with 3-digit is because the output already contains a 3-digit numbers, with your formula the 3-digit numbers become 4-digit
there is a way to map placeholders, such ###, with my numbers 1, 2 or 3 digits, and replace the empty positions with 0?
one way might be
r = Range[1, 10]; AccountingForm[r, 2, NumberPadding -> {"0", ""}]
