Convert dates on Timeline?

Questions
1

Dear All,

Please can you help.
Why are ‘DateFormat’ not properly working on the ‘Timeline’ output?

The date output should be “Day”, “Month” and “Year”. But only work on the first output ‘04/09/2004’ but not on the following two dates. Why?

Please can you help. Thanks. …Jos

DateObject[DateFormat -> {"Day", "/", "Month", "/", "Year"}] ;
TimelinePlot[
 {{
   Labeled[{2004, 04, 09}, Style["Date output OK", Black, Bold, 12]]
   , Labeled[Interval[{{2005, 18, 02}, {2005, 28, 06}}], 
    Style["Date output not OK\nshould be\n18/02/2005 - 28/06/2005", 
     Red, Bold, 12]]
   , Labeled[Interval[{{2012, 01, 08}, {2015, 31, 12}}], 
    Style["Date output not OK\nshould be\n08/01/2012 - 31/12/2015", 
     Red, Bold, 12]]
   }
  }]

6845GraphTimelineComunity.gif
6845GraphTimelineComunity.gif608×228 5.84 KB

2

Your first line:

DateObject[DateFormat -> {"Day", "/", "Month", "/", "Year"}] ;

Doesn’t do anything…

Have a look at the help of timeline. The default interpretation of a list as a date is {y,m,d,h,m,s}. If you want to specify it differently use e.g. DateObjects:

DateObject[{"2005/18/02", {"Year", "/", "Month", "/", "Day"}}]
3

Instead of:
DateObject[DateFormat → {“Day”, “/”, “Month”, “/”, “Year”}] ;

You want:
SetOptions[DateObject, DateFormat → {“Day”, “/”, “Month”, “/”, “Year”}]

Additionally, you will still have to specify your dates in code as {year,month,day}. DateFormat just affects how dates are displayed. Look at the output of DateObject[{2015, 31, 12}]. It interprets this as 31 months and 12 days beyond the year 2015.

4

Dear Sander, Sean,

Thanks for your quick reply and excellent support.

Best Regards,…Jos