plotting an array of dataset with ListPlot

Questions
1

hi, I have a set of datapoints such as

val=3; (*this value is calculated before in the program, so it not known a priori*)
x={0,1,2,3};
data = Table[0, {val}];
For[i = 1, i < val + 1, i++,
 data[[i]] = x+i];

Now I can plot each of these data with ListPlot as

ListPlot[Transpose[{x,data[[1]]}]]

and if I want to plot more than one I can do

ListPlot[{Transpose[{x, data[[1]]}], Transpose[{x, data[[2]]}]}]

but how can I plot all of them in one code single line, by considering that val is calculated before in the program
Is there a way to do something like
For[i = 1, i < val + 1, i++, ListPlot[Transpose[{x,data[*]}]]…]?

I was thinking about the use of Show and overlap the graphs, but probably there is an easier solution

Any tutorial added to the answer is more than welcome
Thanks
Smazzu*

2

I thought I found the solution with

ListPlot[Insert[data,x,1]]

but the x value is not the right one
Smazzu

3

Hi,

 x = {0, 1, 2, 3};

(* do not use For or Do unless it's completely unavoidable *)
data = Table[x[[i]] + i, {i, 1, Length[x]}];
(* note now x and data have the same length *)
Length[x]
Length[data]
(* you can transpose only lists of an equal length *)
Transpose[{x, data}]
(* it's ready to plot *)
ListPlot[%]
(* use Show[] for different types of graphics *)

Not sure about a complete tutorial, but F1 can help, at least simple examples can be found there.
Also try to search the web for solutions, many problems are already solved.

I.M.

4

Thanks but indeed it is not the answer to my problem.
I need to plot all the data in different curves but in the same graph

{{1, 2, 3, 4}, {2, 3, 4, 5}, {3, 4, 5, 6}}

with x as common axis
At the end I want to have a graph with val=3 curves, a kind of static way to plot

Manipulate[ListPlot[Transpose[{x, data[[i]]}]], {i, 1, val,1}]

Thanks
Smazzu