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| How about: DeleteCases[XMLtest, XMLElement[tag_, attributes_, data_] /; tag != "YO", Infinity] |
| Alternatively one could make the statement: Attributes[f] = Listable; This works in the case that the lists contain more than two elements. Henrik |
| This has been discussed already broadly elsewhere - [lexical-and-dynamic-scoping-in-mathematica][1] - [condition-block-module-which-way][2] - [mathematica-module-versus-with-or-block][3] -... |
| I try this code to delete all the attributes of my XMLElements XMLtest = Block[{XMLElement}, XMLElement[tag_, _, content_] := XMLElement[tag, {}, content]; XMLtest] but it doesn't work, I receive this error message ... |
| I simply my last question. Thank you in advance for your help My question was : **May you help me to modify this code in order I can add several conditions on the XMLElements that I want to keep in my XMLObjects. ? I need to keep now too types of... |
| Thank you You perfectly answer to my question. |
| Hello, I have a matrix M[3,3]. After a solve procedure, I obtained these results. {{M[1, 2] -> Cos[?[t]], M[1, 3] -> 0, M[2, 3] -> 0, Cos[?[t]] -> M[3, 1], M[3, 2] -> 0, M[3, 3] -> 1, M[2, 1] -> -Cos[?[t]] Sin[?[t]], M[2, 2] -> Sin[?[t]],... |
| (fyi, the discussion title is a reference to http://community.wolfram.com/groups/-/m/t/449605) |
| Sorry, I have no expertise in linearizing differential equations. |
| And look at the result in the Preview pane, which is below the one in which you're typing. Tht is what your post will look like when it's on the forum. |