User Portlet
| Discussions |
|---|
| Thank you very much Daniel and Chris. As soon as my code finish running, I will try your solutions. Amazing to have this kind of help. Regards Rodrigo |
| Hello, thank you for the suggestion, but I'm not sure how to use it: PowerExpand["(a^b)^c"] == PowerExpand["a^(b*c)"] Gives a result of "False". Ah, I see that I have to use ToExpression: PowerExpand[ToExpression["(a^b)^c"]] ==... |
| In case it might be helpful, I'd also suggest that you look into Dataset. The form that you say you want (`dt` in your original question), is actually not particularly well suited to further queries, or at least not when compared to Dataset. If we... |
| Another excellent implementation! |
| Got the same result (OS X) than you but this was fixed just by setting the option `PlayRange->All` in `Play`. By default this option is set to `Automatic` and according to the docs it says "outlying levels are dropped". This is why you observe that... |
| Thank you. That is helpful. |
| Yes, your approach yields a result that looks like what I want. I didn't say so earlier, because your code had options I'm not familiar with, so I was waiting til I had time to evaluate it. Now that I see what it evaluates to, that is what I'm after.... |
| Dear Chris, Thanks for your reply, tip and help ! Best Regards,....Jos |
| Thanks, Chris P I imported the data from a csv type format (filename = train.csv) using data = SemanticImport[ "C:\\\Users\\\Thadeu\\\Documents\\\Kaggle\\\train.csv"] I'll start a new question. Thanks |
| This is funny too: DiscretizeGraphics[ CountryData["France", {"SchematicPolygon", "Mercator"}]] |