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Hi. In Mathematica, one could use Angle Angle Side. AASTriangle[90 Degree,24 Degree, 46] //N Triangle[{{0.,0.},{42.0231,0.},{0.,18.7099}}] |
Hi. I think you are missing some constraints. const = Thread[ {a, b, n, c1, c2, b - a*n, a - c1, a - c2, b - c1 - c2} >= 0 ] |
Hi. It sounds like your version is working. What I had to do for the Mac, and it appears to work, was the following... Get["EntityFramework`"] However, entering that command now doesn't seem to do anything for me at the moment. Perhaps... |
Hi. You have two Sqrt functions. The larger one is the same concept as the smaller one, and easier for posting here... For a Real solution, the function inside a Sqrt function should be >= 0. If it's negative, we switch to complex. ... |
> ... How I can find using wolfram generate term of sequence Hi. There is also CoefficientList ... (which eliminates the table command) :>) CoefficientList[Series[g[t],{t,0,20}],t] {1,0,-2,0,2,0,-(4/3),0,2/3,... etc} |
Thanks Sander for the feedback. I think your right. If one makes the legs Undirected, then I at least get a value. Seems a little strange to me. Anyway, I think I can make a function to use: FindHamiltonianCycle[g,All] To find all... |
Hi. Don't know if this would be of value. This is a smaller size for posting... Here are all the lists with just 2 1's out of 5 v={1,1,0,0,0}; Permutations[v] ... |
This worked for me using version 10.2: lst = {"50 ft", "8 ft", "16 m", "35 ft", "70 ft", "6 m", "60 ft", "90 ft", "8 ft"}; (UnitConvert[#1, "Meter"] & ) /@ lst ... |
Random selection of pairs |
Hi. path = FindPath[g,1,4,Infinity,All] {{1,2,4},{1,2,3,4}} rules = PropertyValue[g,EdgeLabels] {3 4->D,2 4->C,1 2->A,2 3->B} EdgeList/@(PathGraph/@path) /.rules {{A,C},{A,B,D}} As a side note, notice that you... |