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| I think you shoud integrate 1/V[x] over x from 0 to d to get time: Clear[c, d, V] V[x_] := c Sqrt[x (d - x)]Integrate[1/V[x], {x, 0, d}, Assumptions -> d > 0] You'll obtain pi/c and if c=9 then time is equal to 0.349066.... |