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| Thanks to [Lukas Lang and kglr][1] the answer is as follows: DownValues@System`GeoPlotsDump`iGeoRegionValuePlot = DownValues@System`GeoPlotsDump`iGeoRegionValuePlot /. HoldPattern@ Rescale[#, minMax : {0,... |
| Thank you for the prompt reply |
| Please comment on the following: a = 11.56; 100000 (1 + a/100) // Floor 1000 (100 + a) // Floor a =.;I guess it's a result of numerical computations and settings for accuracy, precision, etc., but nevertheless ... |
| I got this answer (paths) using my own recursive function with the name FindAllPaths (a brilliant one, is it not?). And I just wonder if I can get the same result using built-in graph functions. In my function I have to introduce two additional... |
| Please clarify the question. If you take just 2 elements from your list, I mean 0. + Abs[-1.75447*10^6 - 0.184261 T] + Abs[-2868.55 + a + 0.276392 T]and [mcode]0. + 2 Abs[-31999.5 - 0.221113 T] + Abs[-86832. - 0.1 T] + Abs[86832. +... |
| I think you shoud integrate 1/V[x] over x from 0 to d to get time: Clear[c, d, V] V[x_] := c Sqrt[x (d - x)]Integrate[1/V[x], {x, 0, d}, Assumptions -> d > 0] You'll obtain pi/c and if c=9 then time is equal to 0.349066.... |
| Why don't you just interpolate your data using Interpolation function if you have a regular grid? Say, you've read your data in pts variable. ThenClear[x,y,z] z[x_, y_] = Interpolation[pts][x, y]Hopefully it'll help.... |