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| I am using the bellow code. With opA or opD works but not with opB or opD. Perhaps because in the output B and C is used 10^-6! But why?. Also, in OpB and optC the menu reset to OptA . ![enter image description here][1] ![enter image description... |
| Transpose is used in tree different ways. It spents much time, except when it is added AbsoluteTiming. Why? Thanks. Guillermo Very slow Transpose[{Range[10^5], Range[10^5]}] slow Evaluate[Transpose[{Range[10^5], Range[10^5]}]] ... |
| I have two functions qMultiple1 and qMultiple2 with the same goal . The function qMultiple2 much faster than qMultiple1, the difference is that Integrate[u[t],..] in qMultiple1 is inside of the function and in qMultiple2 is outside. How can be... |
| I wish to square every term of each element of a list. Let me show the pattern (e.g.): Map[(#^2) &, {rf[a], rf[b], rf[a] + rf[b], rf[a] + rf[b] + rf[c]}, {2}] I obtain as output: Out:= {rf(a^2), rf(b^2), rf(a)^2+rf(b)^2,... |
| Dear friends I have a code to make a simulation. Here it is a toy example represented by only two functions (the real code has more than 100 line an spend in my computer 10 minute each simulation) data = RandomVariate[NormalDistribution[1,... |
| Why: AirTemperatureData["LESA", DateObject[{2020, 1}], Mean] and AirTemperatureData["LESA", {DateObject[{2020, 1, 1}], DateObject[{2020, 1, 31}]}, Mean] give different outputs? Thank you Guillermo |
| Given a list of pairs where the first element of the pair is real values and the second element is an integer, how to obtain a new list of a length n ordered by the second elements being the first element If there is a gap in the ordered integers. ... |
| The below example is from [https://www.wolfram.com/language/11/partial-differential-equations/solve-a-poisson-equation-with-periodic-boundary-co.html.es?product=language][1] I have copied the code but some thing is wrong. What is my mistake? ... |
| How can be solved the following PDE using NDSolve or DSolve Derivative[1, 0][c][z, t] + Derivative[2, 0][c][z, t] - c[z, t] == Derivative[0, 1][c][z, t] Initial conditions: At t =0, c(z,0)= 0, 0 |