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| I will say: > Mathematica version **14** is not a magic box that'll spit out a solution to any > problem. > - > All computer algebra systems, including Mathematica, are limited in > their capabilities. Regards M.I. |
| Maybe exist closed-from ,but I didn't find it only infinte series. $\mathcal{L}_s^{-1}\left[\frac{a \cosh \left(\sqrt{s} y \text{W0}\right) \text{u2}}{a^2+s^2}\right](t)=\sum _{m=0}^{\infty } \frac{(-1)^m a^{1+2 m} t^{1+2 m} \text{u2} \,... |
| &[Wolfram Notebook][1] [1]: https://www.wolframcloud.com/obj/9d6afb42-490f-4638-b6d3-5c3483c841b2 |
| &[Wolfram Notebook][1] [1]: https://www.wolframcloud.com/obj/fff609bc-8480-4161-9235-caed3a0628c1 |
| **ChatGPT AI says:** Yes, in the Wolfram Language, it is generally safe to use `JacobiSymbol` instead of `KroneckerSymbol` when dealing with integer arguments, with a few considerations: 1. **Definition and Generality**: - The... |
| For ordinary users this information is hidden what **NCaputoD** methods uses,but using command **Trace**: Trace@NCaputoD[(2 Log[1 - x] (x + Log[1 - x]))/x^2, {x, 1/2}, -1] (*... NIntegrate...*) we see a command **NIntegrate** by... |
| Let: ExactNumberQ[1] (*True*) Then give exact answer (by symbol and precision) : Integrate[2 Sqrt[1 - x^2], {x, -1, 1}] (*PI*) If: ExactNumberQ[1.0] (*False*) Integrate[2 Sqrt[1 - x^2], {x, -1, 1.0}] ... |
| &[Wolfram Notebook][1] Should work now. [1]: https://www.wolframcloud.com/obj/72aba69d-487f-4c90-a6f2-15336cea4116 |
| S = Integrate[(\[Alpha] \[Lambda])/(x - 1)^2 (x/(x - 1))^(\[Alpha] - 1) Exp[-\[Lambda] (x/(x - 1))^\[Alpha]], {x, 0, t}, Assumptions -> {0 0, \[Lambda] > 0}] (*Mathematica Can compute the CDF*) (* -1 + E^(-E^(I... |
| LineIntegrate[{x^2, -y}, {x, y} \[Element] Line[{{-1, -1}, {-1, 1}, {1, 1}, {1, -1}, {-1, -1}}]] LineIntegrate[{y^2, -x}, {x, y} \[Element] Line[{{-1, -1}, {-1, 1}, {1, 1}, {1, -1}, {-1, -1}}]] (* 0 *) (* 4 *) I tried with... |