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| They can be. The data set starts out as a list of {X, Y, Z} points that represents a square image. I then partition the data to have the {x, y} points that pass my filters. |
| Hi Rohit, Adding more feedback to your suggestion, I did try the FindClusters to the raw wavelength data and I got the following "clusters": ![cluster][1] You can see that the algorithm didn't group by discrete wavelength islands or bands,... |
| Update: I linear model fit to subtract out was used to remove the tilt. From there I used as subset of the data to isolate only one of the square pillars and then used that as the Kernel for correlation with the original image. The results is a... |
| Thanks! That worked. |
| Update: I get the expected result if I align to the middle of the pulse. ListCorrelate[pulse, sample, Round[Length[pulse]/2], 0]; In general, if two square pulses are convolved, why wouldn't the resultant vector be max in the center? |
| Update:: Solved I was able to solve this using a compound expression (;) inside a while loop structure. I had to change my check statement to prevent an infinite loop, but added an if statement break. Regards Cole |