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I think mathematica does not understand you trig nomenclature, so it is not resolving to the numerical value required by ListPlot.In[19]:= (Sin^2)[1.] Out[19]= (Sin^2)[1.] In[16]:= Sin[1.]^2 Out[16]= 0.708073 |
Discussions |
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I think mathematica does not understand you trig nomenclature, so it is not resolving to the numerical value required by ListPlot.In[19]:= (Sin^2)[1.] Out[19]= (Sin^2)[1.] In[16]:= Sin[1.]^2 Out[16]= 0.708073 |