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I can do DivisorSum[12, DivisorSum[#, # &] &] without any problem--the answer is 55. But how do I use the divisors of the outer sum in the function for the inner sum? I have no problem with Qij[p2_] := DivisorSum[p2,...
This code produces a correct result, but gives an error message: Clear[l, CI] 2 CI[{{2, 2}}] + 2 CI[{{1, 2}, {2, 1}}] /. CI[l_] -> j^(Total[l][[2]]) Total::normal: Nonatomic expression expected at position 1 in Total[l]. ...