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Please note that I have found a workaround for the problem, which is described in my [newer post][1] in the Mathematica group. [1]: https://community.wolfram.com/groups/-/m/t/2820411?p_p_auth=dCJ1gdne
Yes I have tried this method but there is a problem at the numerator. If we do this Simplify[expr, {n1 == n2, n1 + n2 == n}] we obtain (n2 (2 A - 2 c + \[Gamma]1 + \[Gamma]2))/(b (1 + n1 + n2)) At the numerator n1 disappears
Those two definition are very similar, but the evaluation path is different, and there are cases when the outputs are different. One situation I have thought is when the function has the attribute `HoldAll`. The pattern `x_Integer` will not make any...
I'm afraid there is not much you can do right now. Image acquisition on Linux will only be supported starting from 11.3