# User Portlet

Valeriu Ungureanu
Discussions
Our university intends to purchase new computers that are supposed to support CUDA programming in Wolfram Mathematica 12. There is a bit of confusion about the proposed GPU model. Can someone help us to determine if the NVIDIA GTX 1060 6GB DDR5 GPU...
Theory of Games has an impressive development during the last 70 years both as a domain of applied mathematics and a part of various important domains of human activity. It's somewhat strange that Mathematica doesn't include any functionality related...
Dear Community, I have a very simple question relating to ParallelTable[] function. The following code works as it must. In[1]:= ParallelTable[k, {k, 10}] Out[1]= {1, 2, 3, 4, 5, 6, 7, 8, 9, 10} But, if I use Print[], it works as it...
I have to find local and global optima of a function, e.g.: f[x_, y_, z_] := x^3 + y^2 + z^2 + 12 x y + 2 z I use the following Wolfram functions: Maximize[f[x, y, z], {x, y, z}] NMaximize[f[x, y, z], {x, y, z}] ...
Dear All, May someone explain what is wrong with the functions Solve[] and Reduce[] applications when they solve a very simple quadratic equation: $x^2+x+1=0$ This equation has two complex solutions: $\frac{-1 +\sqrt{3} i}{2}$ and...
We have the need to solve in-homogeneous **Fredholm** equations of the second kind: \[CurlyPhi][t] - \[Lambda] \!$$\*SubsuperscriptBox[\(\[Integral]$$, $$a$$, $$b$$]$$K[t, s] \[CurlyPhi][s] \[DifferentialD]s$$\) == f[t] ...
Solve[] and other Wolfram functions submit results as the list of rules. Sometime, there is necessity of transforming the list of rules into a list of values. It may be done, e.g., in the following ways: In[1]:= Table[Subscript[x, i] -> i, {i,...
I have two convergent series. Their convergence is testable in Mathematica: In[1]:= SumConvergence[1/Sqrt[n] - Sqrt[Log[1 + 1/n]], n] Out[1]= True In[4]:= SumConvergence[1/Sqrt[n] Log[1 + 2/(n - 1)], n] Out[4]=...
I used Basic Math Assistant to calculate the product of two radicals: In[24]:= Power[x, (3)^-1] Power[x^2, (3)^-1] Out[24]= x^(1/3) (x^2)^(1/3) ![enter image description here][1] It's obvious that the result must be simplified...
There are many ways to sum positive elements of a list such as, e.g., In[1]:= list = RandomReal[{-10, 10}, 1000000]; In[2]:= tList = { Plus @@ Map[If[# 0] // AbsoluteTiming } Out[2]= {{2.51129,...