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time = TimeUsed[]; Simplify[-((3 t)/4) - 3/8 t Sin[ x[1] + x[2] + x[3] +... + x[18] + x[19] + x[20]] + 3/8 (2 + Sin[x[1] + x[2] + x[3] + ...+ x[18] + x[19] + x[20]])]; TimeUsed[] - time results: 0.07 time =...
Thanks. The problem solves as you said.