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Get a 3D model on this graph?

ONCHUN MATH

Posted 7 years ago

I want to do 3D printing on this graph. But the bottom does not have to be filled. Thank you for your help. ParametricPlot3D[{{t, 1/2 (1 - Abs[t] + Sqrt[1 - t^2]), 1/2 (-1 + Abs[t] + Sqrt[1 - t^2])}, {t, 1/2 (-1 + Abs[t] - Sqrt[1 - t^2]), 1/2 (1 - Abs[t] - Sqrt[1 - t^2])}}, {t, -1, 1}]

POSTED BY: ONCHUN MATH

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Daniel Lichtblau

Daniel Lichtblau, Wolfram Research

Posted 7 years ago

It's one dimensional (a curve) so physical printing in 3D will be a challenge. Might be better to make it a tubular surface.

POSTED BY: Daniel Lichtblau

ONCHUN MATH

Posted 7 years ago

Thank you. I find this way. Improve it plz!! a = ParametricPlot3D[{t, 1/2 (-1 + Abs[t] - Sqrt[1 - t^2]), v}, {t, -1, 1}, {v, 0, 3 + 1/2 (1 - Abs[t] - Sqrt[1 - t^2])}, PlotTheme -> "ThickSurface"] b = ParametricPlot3D[{ t, 1/2 (1 - Abs[t] + Sqrt[1 - t^2]), v}, {t, -1, 1}, {v, 0, 3 - 1/2 (1 - Abs[t] - Sqrt[1 - t^2])}, PlotTheme -> "ThickSurface"]

Thank you. I find this way. Improve it plz!!

a = ParametricPlot3D[{t, 1/2 (-1 + Abs[t] - Sqrt[1 - t^2]), 
   v}, {t, -1, 1}, {v, 0, 3 + 1/2 (1 - Abs[t] - Sqrt[1 - t^2])}, 
  PlotTheme -> "ThickSurface"]
b = ParametricPlot3D[{ t, 1/2 (1 - Abs[t] + Sqrt[1 - t^2]), 
   v}, {t, -1, 1}, {v, 0, 3 - 1/2 (1 - Abs[t] - Sqrt[1 - t^2])}, 
  PlotTheme -> "ThickSurface"]

POSTED BY: ONCHUN MATH