Message Boards Message Boards

1
|
8930 Views
|
4 Replies
|
1 Total Likes
View groups...
Share
Share this post:

Why am I getting the word Return in the output?

Posted 12 years ago
I wrote the following code:
ptable = Map[(3 #^2 - #)/2 &, Range@4500];

For[k = 2250, k > 1, k--, atk = ptable[[k]];
  For[j = k - 1, j >= 1, j--, atj = ptable[[j]];
   If[MemberQ[ptable, atk - atj] && MemberQ[ptable, atk + atj], Return[atk - atj]]]] // Timing

I'm getting the following:
{34.491821, Return[5482660]}

Instead of what I expected:
{34.491821, 5482660}

Why?

thanks,
-Joe
POSTED BY: Joe Gilray
4 Replies
Return is only use for functions, not for For-loops, you simply remove 'Return[]' for the case of a For-loop, it will return atk - atj.
POSTED BY: Sander Huisman
 boo := Module[{},
   ptable = Map[(3 #^2 - #)/2 &, Range@4500];
   For[k = 2250, k > 1, k--,
    atk = ptable[[k]];
    For[j = k - 1, j >= 1, j--,
     atj = ptable[[j]];
     If[MemberQ[ptable, atk - atj] && MemberQ[ptable, atk + atj],
      Return[atk - atj, Module]]
     ]
   ]
  ]
Now
boo // Timing
{22.401744, 5482660}
POSTED BY: Nasser M. Abbasi
Posted 12 years ago
Thanks for the help... I'm still learning some of the basics it seems!
POSTED BY: Joe Gilray
The following code is faster, and in your PC much faster than mine...

In my Pc, i get: boo // Timing, = {33.633816, 5482660}.

But with:

JesusCA =
Compile[{{kk, _Integer}},
Module[{}, ptable = Map[(3 #^2 - #)/2 &, Range@4500];
k = kk; out = 0; While[And[k > 1, out == 0],
atk = ptable[];
Do[atj = ptable[];
If[MemberQ[ptable, atk - atj] && MemberQ[ptable, atk + atj],
out = atk - atj;]
, {j, k - 1, 1, -1}]; k--]; out
], RuntimeAttributes -> {Listable}, Parallelization -> True];

JesusCA[2250] // Timing
 
{24.866559, 5482660}

My pc is slower than yours, but my code in faster. Bye.
Reply to this discussion
Community posts can be styled and formatted using the Markdown syntax.
Reply Preview
Attachments
Remove
or Discard

Group Abstract Group Abstract