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Investigation - power outages in the UK

Posted 6 years ago
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POSTED BY: Henry Jaspars
7 Replies
POSTED BY: EDITORIAL BOARD
Posted 6 years ago
POSTED BY: Henry Jaspars
POSTED BY: Kapio Letto
Posted 6 years ago

With regards to the variable names, I have just amended that. Thank you for pointing that out!

Although I agree that a normal distribution is not perfect here, observe how far the 49.5 Hz reading lies from the mean:

In[1]: (Mean[Last/@frequencies] - 49.5)/StandardDeviation[Last/@frequencies]

Out[1]: 8.57123

Regardless of choice of distribution, 8.57 standard deviations from the mean is a remarkable outlier. Which distribution would you suggest as opposed to the normal (I considered Student's T, but this was not successful)?

POSTED BY: Henry Jaspars
POSTED BY: Ahmed Elbanna
Posted 6 years ago
POSTED BY: Henry Jaspars
POSTED BY: Ahmed Elbanna
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