# Discussion on ComplexPlot and a problem from Kobe U

Posted 1 year ago
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Posted 16 days ago
 I will only add the note that one can also use ToRules[] to get the results of Reduce[] in a more usable form: Simplify[ToRadicals[z /. {ToRules[Reduce[z^3 - 2 Abs[z] + 1 == 0 && Abs[Im[z]] > 0, z]]}]] {-(1/2) I (-I + Sqrt), 1/2 I (I + Sqrt), 1/4 (1 - Sqrt - I Sqrt[18 - 6 Sqrt]), 1/4 (1 - Sqrt + I Sqrt[18 - 6 Sqrt]), (1/(2 6^(2/3)))(-4 (3/(9 + Sqrt))^(1/3) + (2 (9 + Sqrt))^(1/3) - I 6^(1/6) Sqrt[-24 + 24 3^(1/3) (2/(9 + Sqrt))^(2/3) + 2^(1/3) (3 (9 + Sqrt))^(2/3)]), (1/(2 6^(2/3)))(-4 (3/(9 + Sqrt))^(1/3) + (2 (9 + Sqrt))^(1/3) + I 6^(1/6) Sqrt[-24 + 24 3^(1/3) (2/(9 + Sqrt))^(2/3) + 2^(1/3) (3 (9 + Sqrt))^(2/3)])} where I have also elected to use ToRadicals[] to see the solutions in radical form. Answer