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Filling using ListCurvePathPlot

Posted 11 years ago
Hey

Hope you can help me.

I have a list of points which forms a "circle", i then use ListCurvePathPlot to plot this "circle". What i then would like to so is to use Filling to color the inclosed region, however i can not get this to work with ListCurvePathPlot.
Any suggestions ?

I know that i can split the region in two functions which then can be interpolated and then use Plot and filling. But I really look for a solution that could avoid this extra work, as it seems logical tome to fill the region that ListCurvePathPlot inclose.

Regards Ole
POSTED BY: Ole Svendsen
Here is an example solution:
data = Table[{Cos[t], Sin[t]}, {t, Range[0, 2 Pi, 0.01]}];
ListLinePlot[data, AspectRatio -> 1, Filling -> 0]


If the data points are unordered they need to be put in order:
 (* starting with ten unordered points *)
 data = Table[{Cos[t], Sin[t]}, {t, RandomReal[{0, 2 Pi}, 10]}];
 
 Needs["ComputationalGeometry`"];
 
 (* arrange points in order *)
 anticlockwise = data[[Sequence@ConvexHull[data]]];
 sorted = Append[#, First[#]] &@anticlockwise;
 
ListLinePlot[sorted, Filling -> sorted[[1, 2]],
AspectRatio -> 1, FillingStyle -> LightBlue]


Demonstration with multiple data sets:
 (* creating 10 data sets, each with 30 unordered points *)
 Array[(c[#] = ({dx1, dy1, sz1} = RandomReal[{1, 4.5}, 3];
       data = Table[0.1 sz1 {Cos[t], Sin[t]} + {dx1, dy1},
         {t, RandomReal[{0, 2 Pi}, 30]}])) &, 10];
 
 Needs["ComputationalGeometry`"];
 
 Array[(s[#] = (data = c[#];
       anticlockwise = data[[Sequence@ConvexHull[data]]];
      sorted = Append[#, First[#]] &@anticlockwise)) &, 10];

Show[Array[ListLinePlot[s[#], Filling -> s[#][[1, 2]],
    AspectRatio -> 1, FillingStyle -> LightBlue] &, 10],
PlotRange -> {{0, 5}, {0, 5}}, AxesOrigin -> 0, Frame -> True]
POSTED BY: Chris Degnen
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