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Why wolfram returns a bad response to a limit?

Posted 12 years ago

A friend asked me about a limit, use it to check your answer wolfram but ... wolfram returns another value

lim (x to -infinity ) ((x+5sqr(4+x²))/((9+8x³)^(1/3)))
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POSTED BY: Eduen Sarceno
6 Replies
POSTED BY: Marco Thiel
Posted 12 years ago
POSTED BY: Eduen Sarceno

All depends on how that cube root is done. To get surd behavior one requires CubeRoot (or Surd) in Mathematica.

In[154]:= Limit[(x + 5*Sqrt[4 + x^2])/CubeRoot[9 + 8*x^3], 
 x -> -Infinity]

(* Out[154]= -2 *)

In[155]:= Limit[(x + 5*Sqrt[4 + x^2])/(9 + 8*x^3)^(1/3), 
 x -> -Infinity]

(* Out[155]= 1 - I Sqrt[3] *)

As for Wolfram|Alpha, I do not know offhand what heuristics it uses to determine which was intended. But one can force the surd behavior by using cbrt().

lim (x to -infinity ) ((x+5sqr(4+x.b2))/cbrt(9+8x.b3)) enter image description here

POSTED BY: Daniel Lichtblau
Posted 12 years ago

Not really, see you here

POSTED BY: Eduen Sarceno
Posted 12 years ago

Not really, see you here

POSTED BY: Eduen Sarceno

Hi,

the problem is with your calculation on the board. The solution will be complex because the cubic root in the denominator will go negative as x tends to infinity. The step from your second to the third term and from the third to the fourth appear to be incorrect.

Cheers, Marco

POSTED BY: Marco Thiel
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