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How to change the form and color of the asymptote?

Wen Dao

Posted 1 day ago

f[x_] := 1 - 1/(x - 9/2) Plot[f[x], {x, 0, 10}, Filling -> Axis, Ticks -> {Range[20], Automatic}, AxesOrigin -> {0, 0}, ExclusionsStyle -> Directive[Dashed, AbsoluteThickness[0.5], Red], Exclusions -> "Discontinuities"] In the above code, why is this segment of code unable to change the style and color of the automatically generated asymptotes? How can we set and modify the style and color of the asymptotes? ExclusionsStyle -> Directive[Dashed, AbsoluteThickness[0.5], Red]

f[x_] := 1 - 1/(x - 9/2)  
    Plot[f[x], {x, 0, 10}, Filling -> Axis, 
     Ticks -> {Range[20], Automatic}, AxesOrigin -> {0, 0}, 
     ExclusionsStyle -> Directive[Dashed, AbsoluteThickness[0.5], Red], 
     Exclusions -> "Discontinuities"]

In the above code, why is this segment of code unable to change the style and color of the automatically generated asymptotes? How can we set and modify the style and color of the asymptotes?

ExclusionsStyle -> Directive[Dashed, AbsoluteThickness[0.5], Red]

enter image description here

POSTED BY: Wen Dao

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Eric Rimbey

Posted 16 hours ago

Unfortunately, I don't know how to produce what you want, but I can tell you that the problem is due to setting `Filling`. If you can do without `Filling` then you'll get your asymptote. If you need the filling, then you might need to create your own composite plot.

POSTED BY: Eric Rimbey

Wen Dao

Posted 11 hours ago

The asymptote is not displayed in red.

POSTED BY: Wen Dao

Wen Dao

Posted 11 hours ago

If you want both the effect of filling and the ability to freely change the style and color of the automatically generated function asymptote, how should the code be set?

POSTED BY: Wen Dao

Gianluca Gorni

Gianluca Gorni, University of Udine

Posted 15 hours ago

An explicit `Exclusions` value changes the appearance of the asymptote: f[x_] := 1 - 1/(x - 9/2); Plot[f[x], {x, 0, 10}, Filling -> Axis, Ticks -> {Range[20], Automatic}, AxesOrigin -> {0, 0}, ExclusionsStyle -> Directive[Dashed, AbsoluteThickness[0.5], Red], Exclusions -> 9/2] Anyway, in this case I would recommend `Exclusions -> "Singularities"` instead of `"Discontinuities"`.

An explicit Exclusions value changes the appearance of the asymptote:

f[x_] := 1 - 1/(x - 9/2);
Plot[f[x], {x, 0, 10}, Filling -> Axis, 
 Ticks -> {Range[20], Automatic}, AxesOrigin -> {0, 0}, 
 ExclusionsStyle -> Directive[Dashed, AbsoluteThickness[0.5], Red], 
 Exclusions -> 9/2]

Anyway, in this case I would recommend Exclusions -> "Singularities" instead of "Discontinuities".

POSTED BY: Gianluca Gorni

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