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Mathematica TreePlot add duplicate elements in subtrees?

Posted 9 years ago

Is it possible to add p2 to both SysVar2,3 like I drawn ? Tree View

POSTED BY: bogd timo
9 Replies

It can be done quite easily using Graph:

 Graph[{Labeled[1, "1"], Labeled[2, "2"], Labeled[3, "3"], 
  Labeled[4, "4"], Labeled[5, "5"], Labeled[6, "5"]}, {1 <-> 2, 
  2 <-> 3, 2 <-> 4, 3 <-> 5, 4 <-> 6}, 
 GraphLayout -> "LayeredDigraphEmbedding"]

In this notation you separate the definitions for connections and for labels.

enter image description here

POSTED BY: Sander Huisman

By the way, the code in this thread shows how to rotate the text in the node labels:

POSTED BY: David Reiss

Something Like this will work--it rotates the entire graph: getting the nodes to rotate back to horizontal is beyond my pay grade ;-)

Rotate[ TreeForm[A["S1", "S2", S3["wtf", B["S1", "f2"]]], 
  DirectedEdges -> True], \[Pi]/2]
POSTED BY: David Reiss
Posted 9 years ago

I found an easy way but the only thing I don't know is how to rotate the TreeForm plot to the left Any Ideas :( TreeForm[Root["S1", "S2", S3["wtf", NewLol["S1", "f2"]]], DirectedEdges -> True]

enter image description here

POSTED BY: bogd timo

I think that it is important to remember that these are Graph rendering functions (in the sense of being graph theoretic) rather than general Graphics functions. Their intent is to create a graphic representation of a graph theoretic data structure which involves edges and vertices.

To (mis) quote Gertrude Stein: "Node is a node is a node is a node."

But.... you could certainly figure out a way to algorithmically change the repeated right hand side vertices (perhaps on a layer by layer basis if that's your need) in a way that appends a different sequence of invisible spaces to each one as appropriate.

POSTED BY: David Reiss
Posted 9 years ago

I used a combination of spaces and replacements , but it gets out of hand quickly. There must be added a feature for this IN THE NEXT MATHEMATICA VERSION FFS !!!

listNodesSubsystemView = Join[{ "XXX" -> "SubSystems"}, 
  Reverse[{"SubSystems" -> "SysVar1", "SubSystems" -> "SysVar2", 
    "SubSystems" -> "SysVar3"}],
   {"SysVar1" -> "p1S1", "SysVar1" -> "p2S1", "SysVar1" -> "p3S1",
    "SysVar2" -> "p1S2", "SysVar2" -> "p2S2", "SysVar2" -> "p3S2",
    "SysVar3" -> "p3S3"}],
  Reverse[{"p1S1" -> "Sp11", "p1S1" -> "Sp12", "p2S1" -> "Sp21", 
    "p2S1" -> "Sp22",(*in system variant S1*)
    "p1S2" -> " Sp11", "p2S2" -> " Sp21", "p3S2" -> " Sp31", 
    "p3S2" -> " Sp32",(*in system variant S2*)
    "p3S3" -> "  Sp31"}]];(*in system variant S3*)
TreeSubSystem = 
 TreePlot[listNodesSubsystemView, Left, 
     First[ First[listNodesSubsystemView]], VertexLabeling -> True, 
     DirectedEdges -> True] /. "p2S1" | "p2S2" | "p2S3" -> "p2" /. 
   "p3S1" | "p3S2" | "p3S3" -> "p3" /. 
  "p1S1" | "p1S2" | "p1S3" -> "p1";

enter image description here

POSTED BY: bogd timo

Well one way, which is a REAL HACK is to replace one of your instances of



"p2 "

I.e. add a space (which can be an invisible space (

But since TreeGraph is crating a connectivity graph, if these two vertices are not different in some way then it will, correctly, display the vertex once with multiple edges linking to it.

POSTED BY: David Reiss
Posted 9 years ago

The code for the pic above is :

  listNodesSubsystemView = 
         Join[{"xxx" -> "SubSystems"}, 
          Reverse[{"SubSystems" -> "SysVar1", "SubSystems" -> "SysVar2", 
            "SubSystems" -> "SysVar3"}], 
          Reverse[{"SysVar1" -> "p1", "SysVar2" -> "p2", "SysVar3" -> "p3", 
            "SysVar3" -> "p2"}], 
          Reverse[{{"p1" -> "Sp11", "value set"}, {"p1" -> "Sp12", 
             "value set"}, {"p3" -> "Sp31", "value set"}, {"p3" -> "Sp32", 
             "value set"}}], {{"p2" -> "Sp21", "value set"}}]; TreeSubSystem =
          TreePlot[listNodesSubsystemView, Left, 
          First[First[listNodesSubsystemView]], VertexLabeling -> True, 
          DirectedEdges -> True]
POSTED BY: bogd timo

Could you give your original code for this so readers could play with it?

POSTED BY: David Reiss
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