I need to solve the following system:
$2 \frac{d A_p} { dx} = -i B A_s$
$\frac{x}{2} \frac{d A_s}{dx} + 3/4 A_s = -i B^* A_p$
$\frac{d^2 B}{ d^2 x} = -A_p A_s^*$
with the initial condition:
$A_p(0)=1$
$A_s(0)=0.1$
$B(0) = -i 0.075$
$ \frac{d B}{ dx} =0$
Can you help me to solve it with Mathematica? Thank you so much!!!
