I need to solve the following system:
2 \frac{d A_p} { dx} = -i B A_s
\frac{x}{2} \frac{d A_s}{dx} + 3/4 A_s = -i B^* A_p
\frac{d^2 B}{ d^2 x} = -A_p A_s^*
with the initial condition:
A_p(0)=1
A_s(0)=0.1
B(0) = -i 0.075
\frac{d B}{ dx} =0
Can you help me to solve it with Mathematica? Thank you so much!!!
