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Mathematica Wolfram Language

swing of the pendulum

Patrik Resch

Posted 10 years ago

I would like to visualize a swing of the pendulum. I want to write a function `springmass[z, nzigzag]`, which will draw the spring (line) and the swinging weight (rectangle) for an default total length `z` and a quantity of spring coils (`nzigzag`). I should animate the motion with exactly this line: Animate[Graphics[springmass[5 + Sin[?], 23],PlotRange -> {-9, 0}], {?, 0, 2 ?}] That's what I found on the internet: With[{min = .4}, vspring[a0_, y10_, y20_] := Module[{a = a0, y1 = y10 + min, y2 = y20, n = 100}, h = (y2 - y1)/n; yvalues = Table[k, {k, y1, y2, h}]; xvalues = Table[a Sin[(m ?)/2], {m, 0, n}]; Line[Transpose[{xvalues, yvalues}]]]] and With[{size = .2}, Animate[ Graphics[{ vspring[0.2, 0, 2 Sin[y]], Red, Thickness[5 size], Line[{{-.5 size, 2 Sin[y]}, {.5 size, 2 Sin[y]}}]}, PlotRange -> {{-size, size}, {-2.2 , 2 size}}], {y, -?, 0, 0.1}]] But I have one question. I should use this line: Animate[Graphics[springmass[5 + Sin[?], 23],PlotRange -> {-9, 0}], {?, 0, 2 ?}] The vspring function of the internet code have 3 parameters and the "required" line (the function springmass) have 2 parameters. How can I change that? Thanks for your help!!!

I would like to visualize a swing of the pendulum. I want to write a function springmass[z, nzigzag], which will draw the spring (line) and the swinging weight (rectangle) for an default total length z and a quantity of spring coils (nzigzag).

I should animate the motion with exactly this line:

Animate[Graphics[springmass[5 + Sin[?], 23],PlotRange -> {-9, 0}], {?, 0, 2 ?}]

That's what I found on the internet:

With[{min = .4}, 
  vspring[a0_, y10_, y20_] := 
    Module[{a = a0, y1 = y10 + min, y2 = y20, n = 100}, 
      h = (y2 - y1)/n; 
      yvalues = Table[k, {k, y1, y2, h}]; 
      xvalues = Table[a Sin[(m ?)/2], {m, 0, n}]; 
      Line[Transpose[{xvalues, yvalues}]]]]

and

With[{size = .2}, 
  Animate[
    Graphics[{
      vspring[0.2, 0, 2 Sin[y]], 
      Red, Thickness[5 size], Line[{{-.5 size, 2 Sin[y]}, {.5 size, 2 Sin[y]}}]}, 
      PlotRange -> {{-size, size}, {-2.2 , 2 size}}], 
    {y, -?, 0, 0.1}]]

But I have one question. I should use this line:

Animate[Graphics[springmass[5 + Sin[?], 23],PlotRange -> {-9, 0}], {?, 0, 2 ?}]

The vspring function of the internet code have 3 parameters and the "required" line (the function springmass) have 2 parameters. How can I change that?

Thanks for your help!!!

POSTED BY: Patrik Resch

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Erik Mahieu

Posted 10 years ago

It is best to give your variables some plain understandable names. Like in you function:( this is a spring with diameter and start and endpoint) springmass[start_: 0, end_, diameter_] := Module[{a = diameter, y1 = start, y2 = end, n = 100}, h = (y2 - y1)/n; yvalues = Table[k, {k, y1, y2, h}]; xvalues = Table[a Sin[(m \[Pi])/2], {m, 0, n}]; Line[Transpose[{xvalues, yvalues}]]] This will then make a simple manipulate: Manipulate[With[{size = .2}, Animate[ Graphics[{ vspring[diameter, start, 2 Sin[y]], Red, Thickness[5 size], Line[{{-.5 size, 2 Sin[y]}, {.5 size, 2 Sin[y]}}]}, PlotRange -> {{-size, size}, {-2.2, 2 size}}, Axes -> True, ImageSize -> Small], {y, -\[Pi], 0, 0.1}]], {{diameter, .2}, .05, 1}, {{start, 0}, -1, 1}] your function springs eliminates the strapping and considers it to be zero:springmass[start: 0, end, diameter_] := Module[{a = diameter, y1 = start, y2 = end, n = 100}, h = (y2 - y1)/n; yvalues = Table[k, {k, y1, y2, h}]; xvalues = Table[a Sin[(m [Pi])/2], {m, 0, n}]; Line[Transpose[{xvalues, yvalues}]]] This way no need for a third variable since the default value _:0 will be chosen. Animate[Graphics[springmass[5 + Sin[\[CurlyPhi]], 1], PlotRange -> {{-5, 5}, {0, 7}}, Axes -> True], {\[CurlyPhi], 0, 2 \[Pi]}] It is better to explain the question more in detail since it was hard to guess what this was all about. But this will hopefully be of help.

POSTED BY: Erik Mahieu

Erik Mahieu

Posted 10 years ago

It is best to give your variables some plain understandable names. Like in you function:( this is a spring with diameter and start and endpoint) springmass[start_: 0, end_, diameter_] := Module[{a = diameter, y1 = start, y2 = end, n = 100}, h = (y2 - y1)/n; yvalues = Table[k, {k, y1, y2, h}]; xvalues = Table[a Sin[(m \[Pi])/2], {m, 0, n}]; Line[Transpose[{xvalues, yvalues}]]] This will then make a simple manipulate: Manipulate[With[{size = .2}, Animate[ Graphics[{ vspring[diameter, start, 2 Sin[y]], Red, Thickness[5 size], Line[{{-.5 size, 2 Sin[y]}, {.5 size, 2 Sin[y]}}]}, PlotRange -> {{-size, size}, {-2.2, 2 size}}, Axes -> True, ImageSize -> Small], {y, -\[Pi], 0, 0.1}]], {{diameter, .2}, .05, 1}, {{start, 0}, -1, 1}] your function springs eliminates the strapping and considers it to be zero:springmass[start: 0, end, diameter_] := Module[{a = diameter, y1 = start, y2 = end, n = 100}, h = (y2 - y1)/n; yvalues = Table[k, {k, y1, y2, h}]; xvalues = Table[a Sin[(m [Pi])/2], {m, 0, n}]; Line[Transpose[{xvalues, yvalues}]]] This way no need for a third variable since the default value _:0 will be chosen. Animate[Graphics[springmass[5 + Sin[\[CurlyPhi]], 1], PlotRange -> {{-5, 5}, {0, 7}}, Axes -> True], {\[CurlyPhi], 0, 2 \[Pi]}] It is better to explain the question more in detail since it was hard to guess what this was all about. But this will hopefully be of help.

POSTED BY: Erik Mahieu

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