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Evaluate "Plot" with specific spacing, say 0.1 by 0.1 to 0.9?

Erez A
Posted 10 years ago

Hey,

I have a very "heavy" calculation, which I want to speed-up. How do I tell Mathematica to evaluate "Plot" with specific spacing, say 0.1 by 0.1 to 0.9? Instead of Plot[Func., {x,0.1,0.9}] which let's it choose the spacing itself? In Matlab, this is the difference between [0.1:0.9] and [0.1:0.1:0.9]...

Thanks! Erez .

POSTED BY: Erez A
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Hans Milton
Hans Milton
Posted 10 years ago

The Joined option can be used to let DiscretePlot "fake" a continuous plot:

DiscretePlot[Sin[t], {t, 0, 2, 0.1}, Joined -> True, Filling -> None]

enter image description here
POSTED BY: Hans Milton
David Keith
David Keith
Posted 10 years ago

You can also use PlotPoints to set the number of initial points and MaxRecursion to prevent refinement. Of course the plot quality will suffer. (Mesh->Full just shows the points.)

Plot[Sin[x], {x, 0, 2 Pi}, PlotPoints -> 10, MaxRecursion -> 0, 
 Mesh -> Full]

enter image description here
POSTED BY: David Keith

Hi,

if you DecretePlot, you can use the option Filling->None to get rid of the vertical lines.

DiscretePlot[Sin[t], {t, 0.1, 0.9, 0.1}, Filling -> None]

Cheers,

Marco
POSTED BY: Marco Thiel
Hans Milton
Hans Milton
Posted 10 years ago

Hi Erez,

DiscretePlot does what you are looking for. An example with spacing 0.1:

DiscretePlot[Sin[t], {t, 0, 2, 0.1}]

enter image description here
POSTED BY: Hans Milton

Hi,

this is one way:

ListPlot[{#, Sin[#]} & /@ Range[0.1, 0.9, 0.1]]

enter image description here

If you really want, you can do it with Plot, too, but it is really artificial:

Plot[Sin[t], {t, 0.0, 1}, Mesh -> {Range[0., 1, 0.1]}, MeshStyle -> Directive[Red, PointSize -> Large], PlotStyle -> None]

enter image description here

Cheers,

Marco
POSTED BY: Marco Thiel
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