Here is my question: I have to calculate the definite integral from 0
to 1 of a series sum from n= 1 to infinity. The function is
((n+2)/(2^n))x^(n+1) I've tried to use this syntax in WA search
engine:
I am not too familiar with the Wolfram Alpha language syntax. I only use the Wolfram Mathematica language, and the syntax in that language is
f = ((n + 2)/(2^n)) x^(n + 1);
fi = Integrate[f, {x, 0, 1}];
Sum[fi, {n, 1, Infinity}]
And the answer is 1
. May be the above will help you translate that to the Wolfram Alpha syntax more easily now. Wolfram Alpha should also accept Wolfram Mathematica syntax as far as I know. So the above should works as is inside Wolfram Alpha but I have not tried it.