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how to integrate a sum series?

Posted 10 years ago
5 Replies

Hi Marco, tnx for Your suggestion, it works. However this is not the only problem. I needed the output in this form: 1/(2^0)+1/(2^1)+1/(2/2)+...+1/(2^n) Is there some costruct either in Wa or in Mathematica that gives me the answer in that form? Tnx :-) Eugenio

Hi,

alternatively, you can use a free tier of the Development Cloud. This gives:

enter image description here

Cheers,

Marco

POSTED BY: Marco Thiel

however WA only find the roots of the equation

I am not sure if you typed the correct commands, because there should not be any root finding there. It is just one Integrate command and one Sum command.

If you are interested in Wolfram Language, I would recommend getting Mathematica itself. They also have trial version that you can download and try for free. I think it is 15 days free trial.

POSTED BY: Nasser M. Abbasi

Here is my question: I have to calculate the definite integral from 0 to 1 of a series sum from n= 1 to infinity. The function is ((n+2)/(2^n))x^(n+1) I've tried to use this syntax in WA search engine:

I am not too familiar with the Wolfram Alpha language syntax. I only use the Wolfram Mathematica language, and the syntax in that language is

f = ((n + 2)/(2^n)) x^(n + 1);
fi = Integrate[f, {x, 0, 1}];
Sum[fi, {n, 1, Infinity}]

And the answer is 1. May be the above will help you translate that to the Wolfram Alpha syntax more easily now. Wolfram Alpha should also accept Wolfram Mathematica syntax as far as I know. So the above should works as is inside Wolfram Alpha but I have not tried it.

POSTED BY: Nasser M. Abbasi
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