To add, simply use Contourplot in your endeavours, and use the 'squared' form: y==x^2 rather than 'square-root' form Sqrt[y]==x...

Hmm, interesting... :)

Though, of course, it's still using two Sqrt functions. But, still another interesting approach to it. ;)

Thx, Eric!

So, long and short of it, plot both halves, 'cause there's no other solution? Got it.

Would still prefer there was some way to plot the reflection of the parabola with a single function, rather than 2 half-functions. Ahh well, guess you can't always get what you want, eh? ;)

Or even easier, try ContourPlot!

Okay, so I thought that maybe wrapping the Sqrt[x] in PlusMinus[] would help.

But, apparently, y=PlusMinus[Sqrt[x]] just makes the top half of the graph ALSO disappear. Grr... This is getting frustrating, now. :o(

So, is it possible to graph the entire function in a single go, or am I going to have to individually graph the upper half and the lower half as separate graphs:

Plot[{y = Sqrt[x], y = -Sqrt[x]}, {x, 0, 50}, PlotRange -> {{0, 50}, {-7, 7}}, 
 Ticks -> {{0, 5, 10, 15, 20, 25, 30, 35, 40, 45, 50}, {-6, -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6}}]

I don't feel like I should have to go to these lengths to graph something so simple...

What am I doing wrong? Or what is Mathematica doing wrong, and how do we fix it??