# User Portlet

Discussions |
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I cannot help you further except noting that 1. The original dataset is not newer than 2008 (the paper is from 2010) 2. Mathematica's function `WordFrequencyData` considers only this data set. I suggest you read the documentation on... |

This is incorrect. You area element is `dx dy` if x and y are within the specified area. So, If you want to take this approach you need use the following Integrate[Boole[(E^x + y)^2 + x^2 |

If you discretize, your system will not work against the analytical description of the lens, but rather against a bunch of hyper polygons (in 3D), and any computation you do, will have to consider them all, unless you do some programming yourself.... |

It is also depends on the OS. On my MacBook Pro disk = Graphics[{Black, Disk[{985, 1030}, 600]}, ImageSize -> {2048, 2048}]; ImageDimensions[disk] returns {4096, 4096} So, different behaviors on different... |

There is a right way to pass code here. Anyway, [RightArrow] is the problem you need to use a rule. So just replace the [rightArrow] with -> (see the snippet below) data = Table[{i, Sin[i]}, {i, 0, 2 Pi, 0.1 Pi}]; ListAnimate[ ... |

In the documentation you see that approaching elements of NumericArray systematically is by using Part, therefore the only way of implementing 1+na is using a loop (that generates lists) for example na = NumericArray[Range[10],... |

There is no point of trying this. It is an old unsolved issue at the moment (and for a too long time). If this is for documentation needs, I have seen people writing in Hebrew using MS WORD or similar and pasting PDF "snippets" to Mathematica... |

I suggest that you read on `BinaryWrite` and `BinaryReadList` functions. For a random matrix of the same size you used in the example it takes 0.005651` seconds to store it with 32 bits for each real number (i.e., single precision). It approximately... |

A relevant code snippet would help |

Disregarding physics and considering what you have done only programming-wise 1. Boundary conditions need to be used with equal (==) rather then Set (i.e, a single = sign) 2. There is a problem with the differentiation (the first part) 3. You... |