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| Here's an example showing similar behavior, using ListDensityPlot instead of ListContourPlot. (The principles are the same, but it's easier to see what's going on). We generate some random data and a random polygon. We call ListDensityPlot with... |
| *MODERATOR NOTE: This is the notebook used in the livestream "Dive into Visualization" on Wednesday, August 24 -- a part of Wolfram R&D livestream series announced and scheduled here: https://wolfr.am/RDlive For questions about this livestream,... |
| Join me tomorrow when we look at recently added visualization features, including extensions to scaling functions and ternary plots. I'll also answer questions as time allows and I'm able. Ask them here before the stream or during the live... |
| Right, so you could do something like: ParallelAxisPlot[{data[[{1, 2, 3, 7}]], data[[{4, 5, 6, 9}]], data[[{8}]]}, AxesLabel -> header, PlotLegends -> {"Sony", "Nikon", "Canon"}] ![enter image description here][1] and see that... |
| Add LabelingSize -> Full to the second PieChart: data = {13, 17, 22, 21, 20, 0.6, 1.3, 2.4, 0.8, 1.9}; largeData = Take[data, 5]; smallData = Drop[data, 5]; smallPie = PieChart[smallData, ImageSize -> Tiny, ... |
| Yes, this is a bug. You can work around it with `Method -> {"OptimizePlotMarkers" -> False}`. (I encourage you to send bugs directly to support (\*) to make sure they're properly tracked. You'll also be notified when they are fixed.) \*... |
| How about I widen the location? What makes you think you've got the right Jackson and Memphis? [mcode]allcities = CityData[]; jackson = Select[allcities, First[CanonicalName[#]] === "Jackson" &]; memphis = Select[allcities, First[CanonicalName[#]]... |
| x2 and x3 were eliminated using the linear equality constraints, so they don't show up in the StepMonitor. |
| Here are a couple ways of inputing this question into WolframAlpha. First, you can use something like "1-89-90 triangle side lengths" [link] to get the relative sizes of... |
| In[7]:= Dot[heads, arguments] /. Times -> (#1[#2] &) Out[7]= f + g + h + k Of course, this will break if one of the arguments has head Times. And while it's frequently safer to use Replace at a specific level is rather than... |