User Portlet
| Discussions |
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| Yes! The formula for weighted mean in the documentation is wrong - but the result is correct. More clearly: In[70]:= nbpoints = 10; d = RandomReal[{-1, 1}, nbpoints]; w = Table[1, nbpoints]; Proba = w/Total@w; (* Probability*) ... |
| Consider travel times between three cities in Romania : TravelTime[Entity["City", {"AlbaIulia", "Alba", "Romania"}], Entity["City", {"Harman", "Brasov", "Romania"}]] TravelTime[Entity["City", {"AlbaIulia", "Alba", "Romania"}], ... |
| It could be natural to use Haar wavelets... But the fit is not very good. |
| Thanks for your answer, Hans. But, excepted both these cases, all the assets of the list are labelled in $, while Schneider Electric and Dassault Aviation are labelled in € and need a conversion. Regards, Claude |
| Hello! I'm trying to simulate counts of (pseudo-) species with different characteristics (rare, medium, abundant). From this point of view, it is quite natural to use Gamma-Poissson mixtures, with convenient parameters for the Gamma... |
| I use version 12.1.1.0, for Windows 11 professional... |
| Thanks a lot Rhoit! I think it's good. |
| Thanks Jim! I didn't though to use a mixture model. Pretty long, but it works: S = StableDistribution[\[Alpha], \[Beta], \[Mu], \[Sigma]] /. mle[[2]]; Print@Show[{Histogram[don, "FreedmanDiaconis", "PDF", PlotRange ->... |
| Hello! According to the documentation, "it is also known as autocorrelation or cross-correlation function (ACF or CCF)" . Consider two series: don2 = {1.4700335660303452`, 3.938502200833952`, -2.3409981833059916`,... |
| Hello everybody! I'd like to compute a cross-correlation function between two series, and tests the associated correlations. So , I installed the R package testcorr, and tried to use it. Here are the data - X and Y: {-642.004, 868.033,... |