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Giulio Alessandrini
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The Wolfram Language has built in support for many standard color model. Among those there is the [L* a* b* color space][1], (LAB henceforth), which may turn out to be particularly useful when it comes to colour processing. The main feature of the...
ComponentMeasurements measures each component independently. An example with an image from the documentation: With[{segmentation = MorphologicalComponents[image]}, Show[ image, Graphics[{Red, Thick, Rotate[Circle...
A possible workflow: - use the Mask Tool in the image toolbar to create a mask of the area you care about (using your mouse); - select Copy > Mask as an image; - use `ComponentMeasurements[mask, "Area"]`.
Sorry for the delay. This is the complete function: [mcode]Compile[{{data, _Real, 1}, {width, _Integer}, {cut, _Real}}, Join[Join[Table[0, {width}], UnitStep[(Take[data, {1 + width, -1 - width}] - (1/#2)* Module[{tot = Total[#1[[1...
What about something like [mcode]f[m_, S_] := With[{ R = 1, n = 3, t = 1}, 1 - Gamma[ m, (m ((2^(2 R) - 1)/S)^(1/n))/ t] (Gamma[m, (m ((2^(2 R) - 1)/S)^(1/n))/t]/Gamma[m]^2)] data = Table[{S, f[#, S] + RandomReal[{-1, 1}]/100}, {S,...
I am not super strong in statistic and I am not sure if I understood your problem correctly. However you don't need LinearModelFit to fit a line between two points, [mcode]sA = (Flatten[ImageData[A488, "Bit16"]] - Flatten[ImageData[A405,...
It seems images one and three have an alpha channel (transparency value). You can take care of it with RemoveAlphaChannel[].
While the second one is definitely a issue with the ColorFunction rendering (and you may consider contacting Wolfram support) I am not able to reproduce what you mention in the second paragraph. Neither the graphic size nor the range are changed in...