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If you copy the actual dash and paste that it will work, as Sander points out it isn't actually a hyphen.
This seems to do what you require AbsoluteTiming[ Position[a = RandomInteger[10^7, 10^6], b = Max[a]]; {b, c}] {0.0947826, {9999991, {33357, 164350, 204442, 426967, 488483, 524782, 602322, 728467, 831565, 868132}}}
I believe this works too Clear[a, b, c, d, e]; Sort /@ Select[Tuples[{a, b, c, d, e}, {3}], Count[#, b]
If you factor the factor you get what you are looking for Factor[Factor[x^2 - 5 x - 8, Extension -> All]] However, just because it doesn't look like what you are expecting doesn't mean its wrong in the case of Sander's example.
You could also extend it to any partition size, for example sets of 3 list = Partition[RandomInteger[{-10, 10}, 160], 3]; AbsoluteTiming[ Select[list, #[[1]] >= -1 && #[[2]] = 1 &]]
If we try NSum[1/Sqrt[n] - Sqrt[Log[1 + 1/n]], {n, 0, Infinity}] It won't evaluate, but NSum[1/Sqrt[n] - Sqrt[Log[1 + 1/n]], {n, 1, Infinity}] 1.96429*10^123
This sorts the list by column 2 with no errors on my end Clear[randomTriples]; randomTriples = Table[{RandomReal[{-1, 1}, 3]}, 100]; SortBy[randomTriples, -#[[All, 2]] &]
I usually find if I get that kind of output it's because I haven't given enough information in the form of limits, i.e. also include an upper value for {l, m, n, o, p, x}. However, if you examine the behaviour of just the first Mod section you will...
This would work, but first I opened the csv file with excel and saved it as an xlsx file. and the file is where MMa first looks for files. data = Flatten[Import["frequency-and-phase-data.xlsx", "Data"], 1]; list = {}; Do[x =...
The first part is quite easy list1 = {1, 3, 4, 7, 10, 12, 15, 17, 19, 24, 26, 29, 32, 35}; list2 = {2, 5, 6, 7, 8, 9, 11, 12, 14, 19, 25, 27, 29, 30}; position = Intersection[list1, list2] There are probably more elegant...