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Get data faster while using PlanetData?

Tomáš Hruš
Posted 8 years ago
POSTED BY: Tomáš Hruš
3 Replies
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POSTED BY: Ian Williams
Tomáš Hruš
Tomáš Hruš
Posted 8 years ago

Sometimes it is faster, sometimes slower:

In[5]:= Table[((PlanetData["Mars", 
        Dated["HelioCoordinates", Today + (Tomorrow - Today) #]] & /@ 
      Range[7]) // Timing)[[1]], 20]

Out[5]= {6.42188, 7.875, 8.78125, 8.59375, 6.84375, 6.84375, 6.89063, 6.8125, 7.125, 8.79688, 6.79688, 6.79688, 6.79688, 6.8125, 7.,  7.51563, 7.1875, 6.82813, 7.71875, 6.70313}
POSTED BY: Tomáš Hruš

With my computer access is faster {4.28125, {{Quantity[0.756971, "AstronomicalUnit"], Quantity[-1.17878, "AstronomicalUnit"], Quantity[-0.0432617, "AstronomicalUnit"]},
POSTED BY: Alexander Trounev
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