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$\int_0^\infty e^{i \pi x} \left(1-(x+1)^{\frac{1}{x+1}}\right) dx$

$\int_0^\infty e^{i \pi x} \left(1-(x+1)^{\frac{1}{x+1}}\right) dx$ enter image description here enter image description here

enter image description here

f[x_] = E^(I*Pi*x)*(1 - (x + 1)^(1/(x + 1))); 
g[x_] = x^(1/x); u := t/(1 - t); 

sub = Im[NIntegrate[(f[(-I t)] - f[( I t)])/(Exp[2 Pi t] - 1), {t,
          0, Infinity}, WorkingPrecision -> 100]]

0.1170836031505383167089899122239912286901483986967757585888318959258587743002\
7817712246477316693025869

m = NSum[f[( t)] , {t, 0, Infinity}, WorkingPrecision -> 100, 
  Method -> "AlternatingSigns"]

0.1878596424620671202485179340542732300559030949001387861720046840894772315646\
6021370329665443217278

m - sub

0.0707760393115288035395280218302820013657546962033630275831727881636184572643\
8203658083188126524252

Is the same as 


{Re[NIntegrate[f[t], {t, 0, Infinity}]], and, 
 Re[NIntegrate[f[t], {t, 0, Infinity I}, WorkingPrecision -> 100]]}

NIntegrate::deodiv: DoubleExponentialOscillatory returns a finite integral estimate, but the integral might be divergent.

NIntegrate::deodiv: DoubleExponentialOscillatory returns a finite integral estimate, but the integral might be divergent.

{0.070776, and, \
0.0707760393115288035395280218302820013657546962033630275831727881636184572643\
8203658083188126617723821}

To be continued.
POSTED BY: Marvin Ray Burns
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MRB=$\sum _{x=0}^{\infty } e^{i \pi x} \left(1-(x+1)^{\frac{1}{x+1}}\right) $ vs M2= $\int_0^\infty e^{i \pi x} \left(1-(x+1)^{\frac{1}{x+1}}\right) dx$ in proper integrals

enter image description here

See this notebook. I got an interesting co-answer here.

enter image description here
POSTED BY: Marvin Ray Burns

POSTED BY: Marvin Ray Burns

POSTED BY: Marvin Ray Burns

So, I could conclude that enter image description here

The following "proof of it is from combining

https://www.quora.com/Why-is-it-that-f-x-e-i-pi-x-left-1-x-1-frac-1-x-1-right-int0-infty-f-t-dt-i-int0-infty-f-i-t-dt

and

https://www.quora.com/How-would-you-prove-for-g-x-x-1-x-lim-limits-N-to-infty-int-limits1-2N-e-i-pi-t-g-t-dt-i-lim-limits-N-to-infty-int-limits-0-2N-frac-g-1-it-exp-pi-t-dt.

Whileenter image description here enter image description here

enter image description here Something similar is shown: enter image description here enter image description here enter image description here enter image description here enter image description here enter image description hereenter image description here enter image description here

That looks like it proves it to me. But I don't see any proof for this.
POSTED BY: Marvin Ray Burns

I won't bring the subject of numerical computation into this discussion, but I spent several years learning to compute the digits of $\int_0^\infty{e^{i \pi x} \left(1-(x+1)^{\frac{1}{x+1}}\right)}dx.$ You can read about my adventure at How to calculate the digits of the MKB constant. If you like numeric computations, of much interest is the story of how I came across this integral, by investigating $\sum _{x=0}^{\infty } e^{i \pi x} \left(1-(x+1)^{\frac{1}{x+1}}\right)$ since the 1990s, at Try to beat these MRB constant records!
POSTED BY: Marvin Ray Burns

POSTED BY: Marvin Ray Burns
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