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How do I get a numerical cube root?

Posted 12 years ago
Hi 
Can't paste code on my machine.

Input

\.b2r = CubeRoot[((¹V)/Pi ) (3/4)];           (* need cube root of \.b2r 3Sqrt[\.b2r] *)

Out put

"\.b2r =" Surd[Quantity[5.46439*10^-69, ("Meters")^3], 3]

I require a numerical value like 1.8 x 10^-23 meters

PS 1V is a calculated volume, but any cube root will do.
Many Thanks
Andrew Pepes
POSTED BY: Andrew Pepes
3 Replies
Posted 11 years ago
POSTED BY: Luca Ivaldi
Posted 12 years ago
Hi Marco

Brilliant, I used it with my variables
\.b2r = Power[Quantity[((¹V)/Pi ) (3/4)], 1/3];
and it gives
"\.b2r =" (Quantity[1.76136*10^-23, "Meters"])
Many Thanks
POSTED BY: Andrew Pepes
Would something like this work?
Power[Quantity[5.46439*10^-69, ("Meters")^3], 1/3]

It gives
Quantity[1.76136*10^-23, "Meters"]
(* 1.76136*10^(-23) m *)

M.
POSTED BY: Marco Thiel
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